14x^2=35x=0

Solution for 14x^2=35x=0 equation:

14x^2=35x=0

We move all terms to the left:

14x^2-(35x)=0

a = 14; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·14·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*14}=\frac{0}{28}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*14}=\frac{70}{28}
=2+1/2
$